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-.5x^2+5x+1024=0
We add all the numbers together, and all the variables
-0.5x^2+5x+1024=0
a = -0.5; b = 5; c = +1024;
Δ = b2-4ac
Δ = 52-4·(-0.5)·1024
Δ = 2073
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{2073}}{2*-0.5}=\frac{-5-\sqrt{2073}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{2073}}{2*-0.5}=\frac{-5+\sqrt{2073}}{-1} $
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